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x^2 +y^2=4 and (x-1)^2 +y^2=1

`x^2 +y^2=4 and (x-1)^2 +y^2=1`

Compute: $${x}^{2}+{y}^{2}=4\ and\ {(x-1)}^{2}+{y}^{2}=1$$

Output: $$ {x}^{2}+{y}^{2}=4\ and\ {(x-1)}^{2}+{y}^{2}=1 == {x}^{2}+{y}^{2}=4\ and\ {(-1+x)}^{2}+{y}^{2}=1 $$ Result:$${x}^{2}+{y}^{2}=4\ and\ {(-1+x)}^{2}+{y}^{2}=1$$

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