Input:
sum(k^2,k,1,x)
Write:
`sum(k^2,k,1,x)`
Output:
$$\sum _{k=1} ^ {x} {k}^{2}== \frac{1}{6}\ x+\frac{1}{2}\ {x}^{2}+\frac{1}{3}\ {x}^{3}$$
Result: $$\frac{1}{6}\ x+\frac{1}{2}\ {x}^{2}+\frac{1}{3}\ {x}^{3}$$
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