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Math Handbook Calculator

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Input:
`series(zeta(2,x))`

Compute:
$$series(\zeta(2,x))$$

Result:
$$(1+x)^{-2}+(2+x)^{-2}+(3+x)^{-2}+x^{-2}$$

LaTeX:
(1+x)^{-2}+(2+x)^{-2}+(3+x)^{-2}+x^{-2}

$$series(\zeta(2,x)) == (1+x)^{-2}+(2+x)^{-2}+(3+x)^{-2}+x^{-2}$$




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